Size of armoured cable 185mm sq can take how many amps
[TIME：2017-4-26 17:17:32] [HIT：533time]
The current carrying capacity of the wire is related to the cross section of the conductor. It is also related to the material, type, laying method and ambient temperature of the wire. The factors affecting the calculation are more complicated. Electric power calculation formula, with the voltage multiplied by the current, this formula is the definition of electric power, always correct, apply to any situation.
For pure resistance circuits, such as resistance wire, lamp, etc, you can use the "square of the current multiplied by the resistance", "the square of the voltage divided by the resistance" formula, which is derived from the Ohm law. But for non-pure resistance circuits, such as motors, can only use the "voltage multiplied by the current" of this formula, because for motors, ohm law does not apply, that is, the voltage and current is not proportional. This is because the motor in operation will produce "back EMF". For example, the external voltage is 8 volts, the resistance is 2 ohms, the back electromotive force is 6 volts, and the current is (8-6) / 2 = 1 (s), not 4. So the power is 8 × 1 = 8 (watts). In addition to say a Joule law, that is, the resistance of the fever that formula, the heating power of "current square multiplied by resistance", which is always correct.
Also take the example above, the motor heating power is 1 × 1 × 2 = 2 (watts), that is, the motor's total power of 8 watts, heating power of 2 watts, the remaining 6 watts for doing Mechanical work.
For 1.5,2.5,4,6,10 mm² of the wire can be multiplied by the number of cross-sectional area of 5 times, that is, from the safe current carrying capacity.
For 16,25 mm² of the wire can be multiplied by the number of cross-section 4 times, that is, from the safe current carrying capacity.
For 35,50 mm² of the wire can be multiplied by the number of cross-3 times, that is, from the safe current carrying capacity.
For 70,95 mm² of the wire can be multiplied by the number of cross-sectional area of 2.5 times, that is, from the safe current carrying capacity.
For 120,150,185mm² wire can be multiplied by the number of cross-sectional area of 2 times, that is, from the safe current carrying capacity.